The function y=px2−4x+qy=px2−4x+q in the x-y plane attains a minimum value. what is the value of xx? 1) p=2p=2 2) q=5

1

Step-by-step explanation:

Given function:

y = px² - 4x + q

To find the points of maxima or minima

= 0

or

2px - 4 + 0 = 0

or

px = 2

or

x = [2 ÷ p]

at p = 2

x = 2 ÷ 2 = 1

To check for minima

> 0

thus,

2p - 0 > 0

2p > 0

for positive value of p function is minimum at x = 1

2) at q = 5 also x = 1 as value of x is independent of q

84.78cm^2

Step-by-step explanation:

first we do pi*r^2.

3.14*6^2=113.04

Then, because we know that 1/4 of the circle is missing, just multiply 113.04 by .75.

113.04*.75=84.78cm^2