Mathematics: The given line passes through the points (-1,-1) and (4.1). what is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (-1,3)? v-19-2(x+4) y-1-} (x+4) 0 - 1 (x+4) (43) v-120x+4)

The given line passes through the points (-1,-1)

marshallmattah

06.01.2022

(-1,-1) and (4.1).

1+1

slope of the line: m= = 2/5

4+1

the slope of the perpendicular line: -5/2 and point (-1,3)

(y-3) = -5/2(x+1)

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RioQNA

02.03.2023

See explanation below.

Step-by-step explanation:

Part A:

(i). They both correct because they could have a third degree polynomial that crosses the x-axis 3 times.

(ii). To find the zero's of the first one, set function equal to zero and use zero factor principle given as:

$\mathrm{Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So, we have:

$\mathrm{Solve\:}\:x+2=0:\quad x=-2\\\\\mathrm{Solve\:}\:x-1=0:\quad x=1\\\\\mathrm{Solve\:}\:x-2=0:\quad x=2$

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