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pearfam98
20.09.2019 •
Mathematics
Which shows how the distributive property can be used to evaluate
56 x 3® 1568 - 3139
13
585
Solved
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Ответ:
Hello,
Let's assume
a the lowest number
b the tallest.
HCF(a,b)=56
LCM(a,b)=1568
a*b=HCF*LCM=(2^5*7^2)*(2^3*7)=2^8*7^3
a=56*x
b=56*y
a*b=56²*x*y==>x*y=2^2*7
The numbers possible are (56*1,56*28),(56*2,56*14),(56*4,56*7)
(56*1,56*28)=(56,1568) is excluded.
(56*2,56*14)=(112,784) has like HCF=112 and not 56.
The answer is (56*4,56*7)=(224,392) which HCF is 56 and LCM=1568.
Ответ:
3)0 to 9-add 9. 2 to 5-add 3. 4 to 1-subtract 3. 6 to -3- subtract 9. (Basically it's either add or subtract a number)
5)dunno, sry