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badgirl2005
03.12.2019 •
Mathematics
The half life of carbon-14 is 5,730 years, assuming you start with 100% of carbon-14, what is the expression for the percent, p(t), of carbon-14 that remains in an organism that is t years old and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism estimated to be 20,000 years old?
hint: the exponential equation for half life s p(t)=ao(0.5)^t/h, where p(t) is the percent of carbon-14 remaining, ao, is the initial amount (100%), t is age of organism in years, and h is the half life.
a. p(t)=100(0.5)^5,730t, 29% remaining
b. p(t)=100(0.5)^5,730/t, 91% remaining
c. p(t)= 5,730(0.5)^100t, 5,710 remaining
d. p(t)=100(0.5)^t/5,730, 9% remaining
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Ответ:
Ответ:
2,601
Step-by-step explanation:
the sum of AP = 51/2 × (1+101)
= 51/2 × 101 = 2,601