Mathematics: The law of cosines is a2+b2 - 2abcosc = c^2 find the value of 2abcosc a. 40 b. -40 c. 37 d. 20 (the sides are 2,4, and 5; a to b is 2, b to c is 4, and a to c is 5.)

The law of cosines is a2+b2 - 2abcosc = c^2 find

Ответ:

gabelawson6996

17.01.2022

A² + b² - 2abcosC = c²

Аngle C lies opposite to the side AB, so "c" in the formula it is AB in your triangle

4² + 5² - 2abcosC = 2²
16 + 25 - 2abcosC = 4
41 - 4 = 2abcosC
2abcosC = 37

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Ответ:

meth77

10.01.2020

Mathematics

Step-by-step explanation:

b us the answer to Imma getting it out

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The law of cosines is a2+b2 - 2abcosc = c^2 find the value of 2abcosc a. 40 b. -40 c. 37 d. 20

(the sides are 2,4, and 5; a to b is 2, b to c is 4, and a to c is 5.)

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