The length of a rectangle is 1 ft more than double the width, and the area of the rectangle is 45 ft2 . find the dimensions of the rectangle.

A = L * W
A = 45
L = 2W + 1

45 = W(2W + 1)
45 = 2W^2 + W
2W^2 + W - 45 = 0
(2W - 9)(W + 5) = 0

W + 5 = 0
W = -5...not this one because it is negative

2W - 9 = 0
2W = 9
W = 9/2
W = 4.5 <=== the width is 4.5 ft

L = 2W + 1
L = 2(4.5) + 1
L = 9 + 1
L = 10 <=== the length is 10 ft

Answer is B

The equation is correct since(log2^10)(log4^8)(log10^4)=log10/log2*log8/log4*log4/log10

=log8/log2

=3

Step-by-step explanation: