Mathematics: The length of a rectangle is 5.7 cm more than 2 times the width. if the perimeter is 32.4 cm what are it’s dimensions

7a+16-3a-7= -11 combine like terms 4a+9= -11 add -9 to both sides 4a = - 20 divide by 4 a= -5 hope this helps...

The length of a rectangle is 5.7 cm more than 2 times

he0gaubong

12.01.2022

Dimensions of rectangle are length = 12.7cm and width=3.5cm

Step-by-step explanation:

Let w be the width of the rectangle.

Given:

The length of a rectangle is 5.7 cm more than 2 times the width.

So, $length = 5.7+2\times w$ ----(1)

Perimeter of the rectangle is 32.4 cm.

The perimeter of the rectangle =2(length + width)

2(length + width)=perimeter

$2((5.7+2\times w)+ w)=32.4$

$5.7+3\times w=\frac{32.4}{2}$

$3\times w=16.2-5.7$

$3\times w=10.5$

$w=\frac{10.5}{3}$

w=3.5cm

width is 3.5 cm

Put the width value in equation 1.

$length = 5.7+2\times 3.5$

length = 5.7+7

length = 12.7cm

length = 12.7 cm

Therefore, Dimensions of rectangle are length = 12.7cm and width=3.5cm

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