The length of two sides of a right triangle are given. find the length of the third side. round to the nearest tenth if necessary let’s: 28 in and 15 in

To solve this problem you must apply the proccedure shown below:

 You must apply the Pythagorean Theorem.

 a) Taking 28 inches as the hypotenuse of the right triangle (the largest side), you have:

 a^2=b^2+c^2

 Where "a" is the hypotenuse, and "b" and "c" are the other sides of the right triangle.

 Then, you have:

 a=28 inches
 b=15 inches

 c^2=a^2-b^2 
 c=√(a^2-b^2)
 c=23.6

 Therefore, the answer is: 23.6 inches

 a) Taking 28 inches as a one the other sides that are smaller than the hypotenuse, you have:

 a=√(b^2+c^2)

 Where "a" is the hypotenuse

 a=31.8 inches

  The answer is: 31.8 inches

Taking the 28 and 15 to be the lengths of two shorter sides, we can get the hypotenuse using the formula;

a²+b²=c², Where a and b are the base and height of the triangle and c is the hypotenuse. 
So, c²=a²+b²
      c²=28²+15²
      c²=784+225
      c²=1009
      c=√1009
        = 31.8

A) 20 in

B) 26 in and it got bigger by 1.3 times

C) 40 in and it got bigger by 2 times

Step-by-step explanation:

A) so the formula for finding perimeter is P= 2(L+W) so its (3+7)*2 = 20

B) if you double 3, 3*2=6 then it is 2*(6+7) = 26. 26/20= 13/20= 1.3 times more

C) if you double 3, 3*2=6 and 7, 7*2= 14 then it is (14+6)*2 = 40. 40/20=2/1 = 2 times more.

Also i couldnt solve D for you but try to solve it using what I wrote below.

Hope it helps :)