The local public pool is a rectangle with two
semicircles.
The area of the rectangle is. ?
Using 3.14 for a and rounding to the nearest meter, the
area of each half circle is. ? m2
The area of the surface of the pool is ??

Step-by-step explanation:

The formula for determining the area of a rectangle is expressed as

Area = length × width

Length = 100 m

Width = 52 m

Area of rectangle = 100 × 52 = 5200 m²

A semicircle is half of a circle

The formula for determining the area of a semicircle is

Area = 1/2 × πr²

Diameter = 52 m

Radius = diameter/2 = 52/2

Radius = 26 m

The area of each semicircle is

1/2 × 3.14 × 26² = 1061.32 m²

The area of the surface of the pool is

1061.32 + 1061.32 + 5200 = 7322.64 m²

D.) (-1, 1), (-1, 5), (-7, 1)

Step-by-step explanation:

The length of the horizontal segment of the triangle graphed is 3.  The length of the vertical segment of the triangle graphed is 2.  Using the Pythagorean theorem, this makes the length of the missing side

2²+3²=c²

4+9 = c²

13=c²

√13 = c

This makes our side lengths 2, 3, and √13.

For choice A our vertices are (-1, 1), (-1, 4), (-6, 1).

This makes the length of the horizontal segment 5 and the length of the vertical segment 3.  This makes the missing side length

5²+3²=c²

25+9=c²

34=c²

√34 = c

This is not proportional to the triangle drawn, so it is not similar.

The vertices of the triangle in option B are (-1, 1), (-1, 5), and (-6, 1).  This makes the horizontal segment 5 units long and the vertical segment 4 units long.  This makes the missing side length

4²+5²=c²

16+25=c²

41=c²

√41=c

These are not proportional to the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice C are (-1, 1), (-1, 4) and (-7, 1).  This makes the length of the horizontal segment 6 and the length of the vertical segment 3.  This makes the missing side length

3²+6²=c²

9+36=c²

45=c²

√45=c

3√5=c

These sides are not proportional to the sides of the triangle drawn, so the triangles are not similar.

The vertices of the triangle in choice D are (-1, 1), (-1, 5) and (-7, 1).  This makes the length of the horizontal segment 6 and the length of the vertical segment 4.  This makes the missing side length

6²+4²=c²

36+16=c²

52=c²

√52=c²

2√13=c

These sides are all twice as long as the sides of the triangle drawn; this

Hope it helps!