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gthif5424
28.01.2020 •
Mathematics
The magnitude m of an earthquake is measured using the formula m=log (x/c) , where x is the measured amplitude of a seismic wave and c is the reference amplitude of one micron. two earthquakes are measured. the amplitude of a seismic wave in the first earthquake is 80 times the amplitude of a seismic wave in the second earthquake. how much greater is the magnitude of the first earthquake than the second earthquake?
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Ответ:
The magnitude of the first earthquake is 2 more than the second earthquake
The function is given as:
And the relationship between the amplitudes is given as:
Assume the magnitudes are M1 and M2.
So, the function can be rewritten as:
Subtract M2 from M1
Apply the quotient property of the logarithm
Expand
Evaluate the common terms
Substitute![x_1 = 80x_2](/tpl/images/0477/5908/f166e.png)
Apply the product property of logarithm
Evaluate the common terms
Evaluate log(80)
Approximate
Hence, the magnitude of the first earthquake is 2 more than the second earthquake
Read more about logarithmic functions at:
link
Ответ:
The first earthquake is 1.9 times greater than the second
Step-by-step explanation:
We need to substract
M1 and M2
M1 - M2 = ㏒(x1/c) - ㏒(x2/c)
by properties of the logarithm
= log(x1) - log(c) - (log(x2) - log(c))
= log(x1) - log(x2)
But, we know that x1 = 80*x2
So,
= log(80) + log(x2) - log(x2)
= 1.903
Ответ:
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