![kolbehoneyman](/avatars/33014.jpg)
kolbehoneyman
30.05.2020 •
Mathematics
The number of milk bottles sold can be determined by the equation:
P 0.35n, where P is the number of bottles of milk and n is the number of
boxes opened. What is the constant of proportionality (unit rate)?
Solved
Show answers
More tips
- W Work and Career Where can you learn to be a flight attendant?...
- C Cities and Countries What time does the Metro open in Moscow?...
- S Style and Beauty How to Get Rid of Under Eye Bruises?...
- F Food and Cooking How to Calculate the Gender of Your Child with Blood?...
- C Computers and Internet IMHO: What is it, why is it important, and how to use it?...
- H Health and Medicine Effective Ways to Treat Colic in Infants...
- H Health and Medicine How to Treat the Flu: A Comprehensive Guide...
- S Style and Beauty 5 Tips for Choosing the Best Ugg Boots...
- C Computers and Internet How to Create a Folder on Your iPhone?...
- C Computers and Internet iPhone SMS Delivery Report: How to Set It Up...
Answers on questions: Mathematics
- M Mathematics Need help with this question plZ...
- M Mathematics True or false: fx) is a function True O B. False...
- H History Joseph stalin sent millions of people to work camps in which area of the soviet union? a) st. petersburg b) moscow c) siberia d) murmansk...
- P Physics A 0.04 kg toy is attached to a 2 meter string that can swing without air resistance from a fixed point. It was brought to a angle 0, as shown, where cos 0 = 0.9 12 m 0 0.04 kg If...
Ответ:
option d is correct x = –10, x = –5, or x = 5
step-by-step explanation:
given : function -![f(x)=x^3+10x^2-25x-250](/tex.php?f=f(x)=x^3+10x^2-25x-250)
one root x=-10
the remainder theorem : solve the polynomial through long division.
using formula p(x) = (x – a) q(x) + r(x).
where, p(x) is the dividend , (x-a) is the divisor or root , q(x) is the quotient , r(x) is the remainder
now we solve the given function using remainder theorem
when remainder is zero our quotient =![x^2-25](/tex.php?f=x^2-25)
i.e,![f(x)=x^3+10x^2-25x-250=(x+10)(x^2-25)](/tex.php?f=f(x)=x^3+10x^2-25x-250=(x+10)(x^2-25))
solve![x^2-25=0](/tex.php?f=x^2-25=0)
therefore, roots of function is -10,5 or-5
hence, option d is correct x = –10, x = –5, or x = 5