Mathematics: The number of traffic accidents that occur on a particular stretch of road during a month follows a Poisson distribution with a mean of 8.1. Find the probability that the next two months will both result in three accidents each occuring in this stretch of road

00.6931.386graph AStep-by-step explanation:...

The number of traffic accidents that occur on

cancerbaby209

29.01.2022

P = 0.00072

Step-by-step explanation:

If the number of traffic accidents that occurs follows a Poisson distribution, the probability that x traffic accidents occurs is:

$P(x)=\frac{e^{-m}(m^x)}{x!}$

Where m is the mean. So replacing m by 8.1 accidents/monts, we get:

$P(x)=\frac{e^{-8.1}(8.1^x)}{x!}$

So, the probability that the next two months will both result in three accidents each occurring in this stretch of road is calculated as:

$P(3)*P(3)=\frac{e^{-8.1}(8.1^3)}{3!}*\frac{e^{-8.1}(8.1^3)}{3!}\\P(3)*P(3)=0.00072$

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lclaudettecarte3550

07.04.2021

0.693

1.386

graph A

Step-by-step explanation:

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