The one-to-one functions g and h are defined as follows. g={(-6, 1), (1, 3), (2, - 4), (3, 0), (8, 5)}

h(x)=x-8/11

Find the following.
g^-1 (3)
h^-1 (x)
(h•h^-1)(-1)

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Ответ:

khamaari

03.11.2022

Mathematics

Ok so how you round is from the tens place in 5.82 the tens place is equal to 80 and you would round to 6 and 1.76 would also be rounded to 2 because is more than 5.so the answer will be 6-2 and that is 4.I hope this helps♡♡♡

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The one-to-one functions g and h are defined as follows. g={(-6, 1), (1, 3), (2, - 4), (3, 0), (8, 5)} h(x)=x-8/11 Find the following. g^-1 (3) h^-1 (x) (h•h^-1)(-1)