Mathematics: The perimeter of sportsland park is 624 yd. the length of the rectangle park is 8 yd more than 3 times the width. find the dimensions of the park.

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The perimeter of sportsland park is 624 yd. the length

kait93

12.03.2022

Let the width of the rectangular park be w yard . And it is given that the length is 8 yd more than 3 times the width . SO length is

(3w+8) yd

The formula of perimeter of rectangle is

Perimeter = 2(length + width)

Substituting the given value of perimeter in the formula, we will get

$624 = 2(w+3w+8)
\\
312 = 4w + 8
\\
304 = 4w
\\
w = 76yd$

So the width is 76 yd and the length is

3(76)+ 8 = 236 yd

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