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29.06.2019 •
Mathematics
The perpendicular bisectors of two sides of a triangle meet at point that belongs to the third side. prove that this is a right triangle.
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Ответ:
Statement : If the perpendicular bisectors of two sides of a triangle meet at point that belongs to the third side then this is a right angle triangle.
Prove:
Let ABC is triangle,
In which DF and EF are the perpendicular bisectors of legs AB and BC respectively.
That is, ∠ FDB = ∠BEF= 90°
Where,![F\in AC](/tpl/images/0029/2636/dcad5.png)
Then By the property of the circumcenter,
F must be mid point of leg AC.
That is, DF ║ BC
⇒ ∠ FDB + ∠ DBC = 180° ( the sum of two adjacent angles on the parallel lines by the same transversal is supplementary )
But, ∠ FDB = 90°
⇒∠ DBC = 90°
⇒ ∠ ABC = 90°
That is, Δ ABC is a right angle triangle.
Ответ: