The product of (3x-2)2x + 5) is represented in the form ax2+bx+c. What are the values of a, b, and c?

Option D - 3 ± i√3

Step-by-step explanation:

The given equation is as following,

x2 - 6x + 12 = 0

Where a =1, b= -6, c= 12

X = -b( +,-)√b^2-4ac /2a

Substituting the values in the equation

X = -(-6)( +,-)√(-6)^2-4(1)(12) /2(1)

X= 6 ( +,-)√36-48 /2

X= 6 ( +,-)√12i /2

X= 6 ( +,-)2√3i /2

X = 2  (3 ( +,-)√3i ) /2

Solving for finding the solution

X =  (3 ( +,-)i√3 )

Therefore, the value of X is (3 (+,-) i√3 )