![Isabella1319](/avatars/29314.jpg)
Isabella1319
21.05.2020 •
Mathematics
The sequence that proves shape I is similar to shape II when applied to shape I is a reflection across the x-axisy-axis, followed by a translation 4567 units right and 2345 units down, and then a dilation by a scale factor of
Solved
Show answers
More tips
- C Computers and Internet What to Do If Your ICQ Gets Hacked?...
- L Leisure and Entertainment How to Land on the Moon: Your Comprehensive Guide...
- T Travel and tourism How to Use a Compass: A Beginner s Guide...
- C Computers and Internet Porn Banner: What It Is and How to Get Rid Of It?...
- C Computers and Internet Отправляем смс через интернет: легко и просто...
- L Leisure and Entertainment The Best Film of 2010: A Look Back at the Academy Awards...
- H Health and Medicine Simple and Effective: How to Get Rid of Cracked Heels...
- O Other How to Choose the Best Answer to Your Question on The Grand Question ?...
- L Leisure and Entertainment History of International Women s Day: When Did the Celebration of March 8th Begin?...
Answers on questions: Mathematics
- M Mathematics Which conversion factor would you use to solve the following problem? How many grams are in 11.9 moles of chromium?...
- M Mathematics Explain how using partial quotients to divide is similar to using the distributive property...
- M Mathematics What is the MEAN of 75, 85, 95, 105...
- S SAT Which statement accurately describes the distribution of sunlight for the regions labeled?...
- H History Why did spanish colonists begin to rely more heavily on the atlantic slave trade by the mid-1500s?...
- B Biology HELP PLZ DESCRIBE HOW THE NEEDS OF CELLS ARE MET BY TISSUES AND ORGANS. Give an example...
Ответ:
a. X-axis
b. 6
c. 2
d.2
Ответ:
Since we want to solve for the variable x, we want to isolate x
a²x + (a - 1) = (a + 1)x ⇒ Distribute x to (a+1). Also, remove parentheses
a²x + a - 1 = ax + x ⇒ Subtract a from both sides
a²x - 1 = ax + x - a ⇒ Add 1 to both sides
a²x = ax + x - a + 1 ⇒ Subtract (ax + x) from both sides
a²x - (ax + x)= ax + x - a + 1 - (ax+x) ⇒ Simplify. Remember that multiplying positive by negative = negative
a²x - ax - x = ax + x - a + 1 - ax - x ⇒ Simplify
a²x - ax - x = -a + 1 ⇒ Factor out the x from a²x - ax - x
x(a² - a - 1) = -a + 1 ⇒ Divide both sides by (a² - a - 1)
x = (-a + 1) / (a² - a - 1)
However, we need to make sure that the denominator does not equal 0. Therefore, you set the denominator = 0 (just use the quadratic formula for this), and it gives that the denominator =0 when a = (1+√5)/2 AND (1-√5)/2
Therefore, the final answer is
x = (-a + 1) / (a² - a - 1) given that a ≠ (1+√5)/2, a ≠ (1-√5)/2