mine9226
13.10.2020 •
Mathematics
The student scores on a history test are normally distributed with an unknown population mean and standard deviation A random sample of 38 scores is taken and results in a sample mean of 85 points and sample standard deviation of 4 points. dr 0,10 0.0 0.025 0.01 0.005 3 1.306 1.690 2.030 2.438 2.724 1.306 1.688 2.028 2.434 2.719 1.305 1687 2.026 2.431 2.715 1.304 1.686 2.024 2.429 2.712 1.304 1685 2.023 2.426 2.708 Find a 90% confidence interval estimate for the population mean using the Student's distribution . Round the final answers to two decimal places.
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Ответ:
The 90% confidence interval = (83.9, 86.1)
Step-by-step explanation:
The formula for confidence interval =
Mean ± z × standard deviation/√n
From the question:
n = 38
Mean = 85 points
Standard deviation = 4 points
Z score for 90% confidence interval = 1.645
85 ± 1.645 × 4/√38
85 ± 1.067416951
Confidence Interval =
85 - 1.067416951
= 83.932583049
≈ 83.9
85 + 1.067416951
= 86.067416951
≈ 86.1
Therefore, the 90% confidence interval = (83.9, 86.1)
Ответ:
The answer is f(x)=1/2x+25