The sum of squares of three consecutive numbers is 77 find the numbers

4,5,6 are the three consecutive numbers. 16, 25 and 36 are their squares.

Step-by-step explanation:

Let the three consecutive numbers be x, (x+1), (x+2)

Now, the squares of these three numbers are  

Sum = 77

∴by the problem ,

{Taking 3 common }

{By factorization}

Therfore,

X can't be negetive

∴

The squares of the three consecutive numbers are 16, 25, 36

The three consecutive numbers whose sum is 77 are 4, 5, 6

9514 1404 393

  C, D, E

Step-by-step explanation:

Vertical asymptotes are found where the denominator is zero. The denominator will be zero when any of its factors is zero. Then the vertical asymptotes are ...

  x = 0   ⇒   x = 0 . . . . . . choice E

  x -1 = 0   ⇒   x = 1 . . . . . choice C

  x +5 = 0   ⇒   x = -5 . . . choice D