The sum of two number is 13 and their product is 42 then what are the two numbers​

6 and 7

Step-by-step explanation:

x + y = 13

xy = 42

I just listed the two equations out and the answer just popped out. The trick to this is just thinking about two numbers that obviously both below 13 that add up to it.  6 and 7 is the solution.

Step-by-step explanation:

N = 3rt^4 - 5rz

now factor r out

N = r(3t^4-5z)

divide by r on both sides

N/r = (3t^4 - 5z)

subtract (3t^4)

N/r - 3t^4 = -5z

now divide by -5 to isolate the variable (z)

= z