Mathematics: The sum of two numbers is 4 1/8 and their difference is 7/8. what are the numbers? explain how you found your answer.

The sum of two numbers is 4 1/8 and their difference

yunggin8243

18.01.2022

x=3

$y=\frac{17}{8}$

Step-by-step explanation:

Firstly, we have to transform what is written in words to equations.

The sum of two numbers is 41/8

If we call the unknown numbers as and , we will have:

$x+y=\frac{41}{8}$ (1)

Their difference is 7/8

$x-y=\frac{7}{8}$ (2)

Now we have a system with two equations and two unknowns. Let's solve it.

Isolating from (1):

$x=\frac{41}{8}-y$ (3)

Substituting (3) in (2):

$\frac{41}{8}-y-y=\frac{7}{8}$ (4)

Isolating :

$\frac{41}{8}-\frac{7}{8}=2y$

$y=\frac{34}{16}=\frac{17}{8}$ (5) This is the value of y

Substituting (5) in (1):

$x+\frac{17}{8}=\frac{41}{8}$ (6)

Finding :

$x=\frac{41}{8}-\frac{17}{8}$

x=3 (7) This is the value of x

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nathan1010

29.10.2020

24 = x

Step-by-step explanation:

Write a proportion. Remeber that same units corresponds with each other.

$\frac{8}{3} = \frac{x}{9}$

Cross multiply

72 = 3x

24 = x

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