marvinsductant6710
06.09.2020 •
Mathematics
The tallest living man at one time had a height of 261 cm. The shortest living man at that time had a height of 42.1 cm. Heights of men at that time had a mean of176.75 cm and a standard deviation of 7.86 cm. Which of these two men had the height that was more extreme?
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Ответ:
the shorter man
Step-by-step explanation:
The average of the heights of the two men is ...
(261 +42.1)/2 = 155.55 . . . cm
This value is lower than the population average, so the shorter man must be farther from average than the taller man is.
The shorter man had the more extreme height.
Ответ:
The shorter man
Step-by-step explanation:
The tallest living man at one time had a height of 261 cm. The shortest living man at that time had a height of 42.1 cm. Heights of men at that time had a mean of 176.75 cm and a standard deviation of 7.86 cm. Therefore, the shorter man had a more extreme height.
(261 + 42.1) ÷ 2 = 155.55 cm
Ответ:
1/4
Step-by-step explanation:
x^2 - x
Take the coefficient of x
-1
Divide by 2
-1/2
Square it
(-1/2)^2 = 1/4
Add it
x^2 -x +1/4