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isabella4141
06.01.2020 •
Mathematics
Two planes left the same airport traveling in opposite directions. the first plane left at 9: 00 a.m. and 2.25 h later, the two planes were 1825 mi apart. the second plane left at 10: 00 a.m. and its average rate was 108 mph slower than the first plane's average rate. what was the first plane's average rate?
let x represent the first plane's average rate.
enter an equation that can be used to solve this problem in the first box. solve for x and enter the first plane's average rate in the second box.
equation:
x = mph
Solved
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Ответ:
d = v * t, where v is the velocity and t is the time.
We have two planes that are traveling in the opposite directions.
d = 2.25 x + 1.25 * ( x - 108 )
1,825 = 2.25 x + 1.25 x - 135
1,825 + 135 = 3.5 x
x = 1,960 : 3.5
x = 560
Equation : 1,825 = 2.25 x + 125 *( x - 135 )
x = 560 mph
Ответ:
Because if you multiply -14*2 you get -28 and if you add -14+2 you get -12. Hope this helps