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ndunn692
22.07.2019 •
Mathematics
The u.s. department of health and human services collected sample data for 772 males between the ages of 18 and 24. that sample group has a mean height of 69.7 inches with a standard deviation of 2.8 inches. find the 99% confidence interval for the mean height of all males between the ages of 18 and 24.
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Ответ:
(69.44, 69.96).
Step-by-step explanation:
Given : Sample size : n= 772
Significance level :![\alpha: 1-0.99=0.01](/tpl/images/0120/7568/92b35.png)
Critical value :![z_{\alpha/2}=\pm2.576](/tpl/images/0120/7568/007ff.png)
Sample mean :![\overline{x}=69.7](/tpl/images/0120/7568/08e66.png)
Standard deviation:![\sigma=2.8](/tpl/images/0120/7568/dafb8.png)
The confidence interval for population mean is given by :-
i.e![69.7\pm(2.576)\dfrac{2.8}{\sqrt{772}}](/tpl/images/0120/7568/06e17.png)
i.e![\approx69.7\pm0.26=(69.7-0.26,\ 69.7+0.26)=(69.44,\ 69.96)](/tpl/images/0120/7568/ee505.png)
Hence, the confidence interval for the mean height ( in inches) of all males between the ages of 18 and 24 is (69.44 , 69.96).
Ответ:
we know that
the volume of the oblique pyramid with a square base is equal to
V=\frac{1}{3}BhV=
3
1
Bh
where
B is the area of the base
h is the height of the pyramid
In this problem
The area of the base is
B=EF^{2}\ units^{2}B=EF
2
units
2
h=AB\ unitsh=AB units
The two formulas to calculate h are
Applying the Pythagoras Theorem
h^{2}=AC^{2}-CB^{2}h
2
=AC
2
−CB
2
> h=\sqrt{AC^{2}-CB^{2}}h=
AC
2
−CB
2
h^{2}=AD^{2}-DB^{2}h
2
=AD
2
−DB
2
> h=\sqrt{AD^{2}-DB^{2}}h=
AD
2
−DB
2
therefore
the answer is
AB and EF
AC, CB and EF
AD, DB and EF