caprisun1440
27.07.2019 •
Mathematics
The weight of a beg of pears at the local market averages 8 pounds with a standard deviation of 0.5 pound. the weight of all the bags of pears at the market closely follows a normal distribution. determined what percentage of bags, to the nearest integer, weighed more than 8.25 pounds.
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Ответ:
Standard deviation = s = 0.5 pounds
We have to find what percentage of bags of pears will weigh more than 8.25 pounds. This can be done using the z score.
We have to convert x = 8.25 to z scores, which will be:
z score = 0.5
From the z table, the probability of z score being greater than 0.5 is 0.3085
Therefore, the probability of a bag to weigh more than 8.25 pounds is 0.3085
Thus 0.3085 or 31% (rounded to nearest integer) of bags of pears will have weight more than 8.25 pounds at the local market.
Ответ:
÷2. ÷2
x=42
That is my work