The width of a rectangular room is 55% of its length. the length of the room is 20 feet. what is the area of the room?

x = 1 ,  y = 1 ,  z = 0

Step-by-step explanation:

Add first equation to third one

-2x + 2y + 3z = 0

+

2x + 3y + 3z = 5

5y + 6z = 5 (4th equation)

Subtract second equation to first one

-2x + 2y + 3z = 0  

-

-2x  - y   +   z = -3

3y + 2z = 3 (5th equation)

Multiply 5th equation by 3

3*(3y + 2z) = 3*3

9y + 6z = 9  (6th equation)

Subtract 6th equation to fourth one

5y + 6z = 5  

-

9y + 6z = 9

-4y = -4  

Solve for y  

-4y = -4  

y = (-4)/(-4)

y = 1

Replace this value in 4th equation and solve for z

5(1) + 6z = 5

6z = 5-5

6z = 0

z = 0

Replace y and z values obtained in first equation and solve for x

-2x + 2y + 3z = 0  

-2x + 2(1) + 3(0) = 0  

-2x + 2 = 0

-2x = -2

x = (-2)/(-2)

x = 1