Mathematics: There are 10 boys and 13 girls in ms. kelso’s homeroom. she is going to select one boy and one girl to act as homeroom representatives for student council. how many different pairs of students could ms. kelso choose? a.) 10 b.) 23 c.) 130 d.) 230

There are 10 boys and 13 girls in ms. kelso’s homeroom.

Ответ:

hazefreedom3885

07.06.2020

The notation for this is ${10 \choose 1} \cdot {13 \choose 1}$ .

Where you should know that ${n \choose k} = \frac{n!}{k!(n-k)!}$

When choosing only one boy and one girl, it becomes simple-ish:

$\frac{10!}{9!} \cdot \frac{13!}{12!} = 10 \cdot 13 = 130$

So I would vote for C, hoping I didn't overlook anything...

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Ответ:

nihadsalim10

21.07.2020

Mathematics

The answer is 10 because 2+18

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There are 10 boys and 13 girls in ms. kelso’s homeroom. she is going to select one boy and one girl to act as homeroom representatives for student council. how many different pairs of students could ms. kelso choose?
a.) 10
b.) 23
c.) 130
d.) 230

Ответ:

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