mcouil9369
27.07.2019 •
Mathematics
There are 3 consecutive positive integers. the product of the first and third integer is 6 more than 6 times the second integer. what is the smallest integer? answer
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Ответ:
(x - 1)(x + 1) = 6x + 6
x^2 - 1 = 6x + 6
x^2 - 6x - 7 = 0
(x - 7)(x + 1) = 0
x - 7 = 0
x = 7
x + 1 = 0
x = - 1
the solutions are (7,0) and (-1,0)
Ответ: