There's a picture can someone me .

E) There are no real solutions

Step-by-step explanation:

Looking at the equation, x^2 +20= 4

It is a quadratic equation since the highest power of x is 2

Equation x^2 +20= 4 can be re- written as

x^2 +20= 4 = x^2 +20- 4 =0

x^2 +16= 0

x^2 + 0x +16= 0 - - - - - - - - -1

Solving with the general formula for quadratic equations,

x = [-b +/- √(b^2 -4ac)]/2a

From equation 1,

a = 1 (coefficient if x^2)

b = 0 (coefficient if x

c = 16 (value of the constant)

Substituting into the formula,

x = [-0 +/- √(0^2 -4×1×16)]/2a

= [0+/-√-64]/2×1

= +/-√-64]/2

= +/-8i/2

x= +/-4i

This is a complex number so,

There are no real solutions