Three points have coordinates A(1,-3), B(5,5) and C(5,9). Find the equation of the perpendicular bisector of (a) AB, (b) BC. Hence find the coordinates of the point
equidistant from A, B and C.

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Ответ:

michaelwarren8728

14.06.2022

Mathematics

A) 14900(1+5.3%)^11
=26296.52 (2dp)

b) 14900(1+5.3%)^27
=60083.094
So it will be 27 years

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Three points have coordinates A(1,-3), B(5,5) and C(5,9). Find the equation of the perpendicular bisector of (a) AB, (b) BC. Hence find the coordinates of the point equidistant from A, B and C.