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assassin42
21.10.2019 •
Mathematics
To evaluate log2(3), autumn reasoned that since log2(2) = 1 and log2(4) = 2, log2(3) must be the average of 1 and 2 and therefore log2(3) = 1.5. use the definition of logarithm to
show that log2(3) cannot be 1.5. why is her thinking not valid?
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Ответ:
log₂(3) = 1.585 ≠ 1.5
Her thinking is not valid because the technique of average is valid only if the graph of the function is a straight line, but the graph of the log function is not a straight line.
Therefore the values cannot be taken by average
Step-by-step explanation:
Given:
log₂(2) = 1
log₂(4) = 2
To evaluate : log₂(3)
Now,
we know that
logₓ(y) =
(Here the log has same base in the numerator and the denominator i.e 10)
therefore,
log₂(3) =![\frac{\log(3)}{\log(2)}](/tpl/images/0339/4164/f52b0.png)
also,
log(2) = 0.3010
log(3) = 0.4771
thus,
log₂(3) =![\frac{0.4771}{0.3010}](/tpl/images/0339/4164/64607.png)
or
log₂(3) = 1.585 ≠ 1.5
Her thinking is not valid because the technique of average is valid only if the graph of the function is a straight line, but the graph of the log function is not a straight line.
Therefore the values cannot be taken by average
Ответ:
x>-1
Step-by-step explanation:
-2x+5<7
subtract 5
-2x<2
divide by -2, the sign changes
x>-1