Mathematics: Tom s tank hold 12.5gallons of gas. Ifgas costs $1.96 pergallon, how much wilIt cost to fill histank?1

Tom s tank hold 12.5gallons of gas. Ifgas costs

Ответ:

alizpleyer

25.01.2022

Mathematics

$24.5 = 1 tank

Step-by-step explanation:

All you have to do is multiply.

Since 12.5 gallons = 1 tank,

and $1.96 = 1 gallon

to get the answer, the equation would be,

$1.96*12.5 = 1 tank

$24.5 = 1 tank

Hope it helps!!

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Ответ:

vaizen9621

05.04.2020

Mathematics

Option C

Step-by-step explanation:

Given expression is $\frac{-5x^3+2x^2+9x+2}{(x^2+2)^2}$

Option A

$\frac{A}{x^2+2}+ \frac{Bx+C}{(x^2+2)^2}$

= $\frac{A(x^2+2)}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}$

= $\frac{Ax^2+2A+Bx+C}{(x^2+2)^2}$

Numerator is a quadratic polynomial, while the expression has the numerator as a cubic .

Therefore, both the expressions are not equivalent.

Option B

$\frac{A}{(x^2+2)^2}+ \frac{Bx+C}{(x^2+2)^2}$

= $\frac{A+Bx+C}{(x^2+2)^2}$

Here, numerator of the expression is a linear polynomial which is not equal to given expression.

Therefore, both the expressions are not equivalent.

Option C

$\frac{Ax+B}{(x^2+2)}+ \frac{Cx+D}{(x^2+2)^2}$

= $\frac{(Ax+B)(x^2+2)}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}$

= $\frac{Ax^3+Bx^2+2Ax+2B+Cx+D}{(x^2+2)^2}$

= $\frac{Ax^3+Bx^2+x(2A+C)+D}{(x^2+2)^2}$

Here, numerator is a cubic polynomial.

Therefore, both the expressions are equivalent.

Option D

$\frac{Ax+B}{(x^2+2)^2}+ \frac{Cx+D}{(x^2+2)^2}$

= $\frac{x(A+C)+(B+D)}{(x^2+2)^2}$

Numerator is a linear polynomial.

Therefore, sum is not equal to the given expression.

Option C will be the answer.

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Tom's tank hold 12.5
gallons of gas. If
gas costs $1.96 per
gallon, how much wil
It cost to fill his
tank?1

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Tom's tank hold 12.5gallons of gas. Ifgas costs $1.96 pergallon, how much wilIt cost to fill histank?1

Ответ:

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Ask your question to the AI advisor

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Tom's tank hold 12.5
gallons of gas. If
gas costs $1.96 per
gallon, how much wil
It cost to fill his
tank?1