Tracy is making peanut butter and jelly sandwiches. She has a choice between white, wheat, and rye bread. Three flavors of jelly, and creamy or chunky peanut butter. How many different sandwiches can she make?

She can make 18 different sandwiches

Step-by-step explanation:

A sandwich is composed by bread, jelly and peanut butter.

She has three possible choices of bread(white, wheat and rye).

She has three flavors of jelly.

She also has two possible options for peanut butter(creamy or chunky).

So, the number of options is:

3*3*2 = 18

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

24x2+25x−47=(−8x−3)(ax−2)−53

You should then multiply (−8x−3) and (ax−2) using FOIL.

24x2+25x−47=−8ax2−3ax+16x+6−53

Then, reduce on the right side of the equation

24x2+25x−47=−8ax2−3ax+16x−47

Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and

Step-by-step explanation:

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53Then, reduce on the right side of the equation

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53Then, reduce on the right side of the equation24x2+25x−47=−8ax2−3ax+16x−47

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53Then, reduce on the right side of the equation24x2+25x−47=−8ax2−3ax+16x−47Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53Then, reduce on the right side of the equation24x2+25x−47=−8ax2−3ax+16x−47Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is th