Two dice are rolled; find the probability for total: a) 1, b) 4 or 6; c) <13

0 ; 2/9 ; 1

Step-by-step explanation:

In a roll of two dice ;

The sample space = (Number of faces on die)^number of dice rolled = 6^2 = 36

The total possible outcome = sample space = 36

The probability of an event (A) :

P(A) = number of required outcome / number of total possible outcomes

find the probability for total: a) 1,

P(total of 1)

Number of 1 total = 0

Hence, P(total of 1) = 0

b) 4 or 6;

Number of 4 total = 3

Number of 6 total = 5

3 /36 + 5 / 36 = 8/36 = 2/9

c) <13

P(total < 13)

Number of total < 13 = 36

36 / 36 = 1

both increase abt the same amount

I hope this helped, please mark brainliest, thank you!!