Mathematics: Two sides of an isosceles triangle measure 6 and 10. the perimeter of the triangle could be a. 26 or 21 b. 12 or 20 c. 22 or 23 d. 26 or 22

Two sides of an isosceles triangle measure 6 and

sofiakeogh1670

25.03.2020

Area = 72in^2

Step-by-step explanation:

Your question is incomplete without an attachment (See attachment)

Required

Determine the area of the shaded part

From the attachment;

Assume that the shaded portion is closed to the right;

Calculate the Area:

Area_1 = Length * Width

Area_2 = 8in * (6in + 6in)

Area_2 = 8in * 12in

Area_1 = 96in^2

Next;

Calculate the Area of the imaginary triangle (on the right)

$Area_2 = \frac{1}{2} * base * height$

$Area_2 = \frac{1}{2} * (6in + 6in) * 4in$

$Area_2 = \frac{1}{2} * 12in * 4in$

$Area_2 = \frac{1}{2} * 48in^2$

Area_2 = 24in^2

Lastly, calculate the Area of the Shaded Part

Area = Area_1 - Area_2

Area = 96in^2 - 24in^2

Area = 72in^2

Hence,

The area of the shaded part is 72in²

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