Un químico agrega cierta cantidad de una solución de 86% de alcohol a 11 litros de otra solución al 71% de alcohol y obtiene una solución al 77% de alcohol encuentre la cantidad de litros de la primera solución que se agregaron a la segunda

Step-by-step explanation:

Sea x la cantidad de litros de la mezcla al 86%

x× 86% + 11 × 71% = (x + 11) × 77%

0.86x + 7.81 = 0.77x + 8.47

we know that

the volume of the oblique pyramid with a square base is equal to

V=\frac{1}{3}BhV=

3

1

Bh

where

B is the area of the base

h is the height of the pyramid

In this problem

The area of the base is

B=EF^{2}\ units^{2}B=EF

2

units

2

h=AB\ unitsh=AB units

The two formulas to calculate h are

Applying the Pythagoras Theorem

h^{2}=AC^{2}-CB^{2}h

2

=AC

2

−CB

2

> h=\sqrt{AC^{2}-CB^{2}}h=

AC

2

−CB

2

h^{2}=AD^{2}-DB^{2}h

2

=AD

2

−DB

2

> h=\sqrt{AD^{2}-DB^{2}}h=

AD

2

−DB

2

therefore

the answer is

AB and EF

AC, CB and EF

AD, DB and EF