Use the zero product property to find the solutions to the equation 6x2 – 5x = 56. x = –8 or x = 7/6
x = -8/3 or x = 7/2
x = -1/2 or x = 56/3
x = -3/7 or x = 2/3

A)We have been given →

Hieght of trough = 5m

length of trough = 6m

Breadth of trough = 4m

so , As the top is opened for feeding animals.

Area of base = length× Breadth

= (6×4) m²
= 24 m²

Area of Front and back face = Hieght × length

= (5×6) m²
= 30m²

Area of side faces = hieght × Breadth

= (5×4) m²
= 20 m²


B)Total Surface area of trough will be given by formula - 2(lb+bh+hl)

= 2{(6×4)+(4×5)+(5×6)}

= 2{24+20+30}

= 2×74

= 148 m²

As we have been told top is open , so we will deduct top from Total surface Area to obtain Surface area →

(148-24) m²

(Area of top will be same as base area , that is 24m² as we have solved in A)

= 124m²

Answer→ Surface area of trough is 124m²