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yayalovebree
05.04.2021 •
Mathematics
we want to find the zeros of this polynomial:
p(x)=(x-1)(x+3)(2x+1)
plot all the zeros (x-intercepts) of the polynomial in the interactive graph.
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Ответ:
Step-by-step explanation:
To find the zeros of this polynomial, set the polynomial equal to zero, and then set each of the factors equal to zero separately. Solve each equation for x:
x - 1 = 0 yields x = 1. The x-intercept is (1, 0).
x + 3 = 0 yields x = -3. The x-intercept is (-3, 0).
2x + 1 = 0 yields x = -1/2 The x-intercept is (-1/2, 0)
Ответ:
(- 3, 0), (- 1/2, 0), (1, 0)
Step-by-step explanation:
p(x)=(x-1)(x+3)(2x+1)
Plug p(x) = 0
Therefore,
(x-1)(x+3)(2x+1) = 0
x - 1 = 0 or x + 3 = 0 or 2x + 1 = 0
x = 1 or x = - 3 or x = - 1/2
Hence, (- 3, 0), (- 1/2, 0), (1, 0) are zeroes of the given polynomial
Ответ: