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Gabr02
18.09.2019 •
Mathematics
"what are the largest values of n for which n! has fewer than 100 decimal digits
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Ответ:
ln n! = approx n ln n - n
so if we try n = 60 this gives 4.2796 * 10^80
so we could try higher values:-
n = 65 gives an 89 digit number
n = 70 gives 98 digit number
n=71 gives me an memory error on my calculator!
Lets try an online calculator
Web2.0 calculator gives a 101 digit number or n=71
70 is your answer
Ответ:
(x-1)(x^2+5x-3)