Mathematics: What are the period p and frequency t of oscillation of a pendulum of length one halfft? (hint: upper p equals 2 pi startroot startfraction upper l over 32 endfraction endroot,where l is the length of the pendulum in feet and the period p is in seconds.)

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What are the period p and frequency t of oscillation

vavzincakjoey

08.01.2022

$P'=P \sqrt{\dfrac{1}{2}}$

T ' = √2 T

Step-by-step explanation:

Given that

Time period = P

Frequency = T

We know that time period for pendulum given as

$P=2\pi \sqrt{\dfrac{L}{g}}$

When the length become half then time period will become p'

L'=L/2

$P'=2\pi \sqrt{\dfrac{L'}{g}}$

$P'=2\pi \sqrt{\dfrac{L}{2g}}$

$P'=P \sqrt{\dfrac{1}{2}}$

It means that time period will become 0.707 P.

We know that frequency T

T= 1 /P

T' = 1/P'

T'=√2/P

T ' = √2 T

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