What are the roots of the equation 2x^2 + 9x divided by 6=0?

2x^2 + 9x =6×0 so 2x^2 + 9x = 0 so we factorise x and we get x×(2x+9)=0 so x=0 divided by 2x+9 so it is 0 one root, 2x+9=0 divided by x so we get 2x+9=0 and 2x=-9 and x=-9÷2 and the second root is -4.5. I hope it is helpful. Please give me brainliest

2x^2 + 9x =6×0 so 2x^2 + 9x = 0 so we factorise x and we get x×(2x+9)=0 so x=0 divided by 2x+9 so it is 0 one root, 2x+9=0 divided by x so we get 2x+9=0 and 2x=-9 and x=-9÷2 and the second root is -4.5. I hope it is helpful. Please give me brainliest

Step-by-step explanation:

Fifty- seven If you have to capitalize, capitalize the F in Fifty