What are the roots of the quadratic equation below?

Ответ:

gamer0078

12.06.2021

[see below]

Step-by-step explanation:

Assuming that the equation is:

2x^2+2x+11=0

I graphed the given equation on a graphing calculator.

The roots of a quadradic equation are the x-intercepts of the function.

On the graph the parabola intercepts the points (-4.871, 0) and (-1.129, 0).

Therefore, -4.871 and -1.129 are the roots to the equation.

If we used the quadradic formula...

$\frac{-12\pm\sqrt{12^2-4*2*11} }{2*2}\\\\\frac{-12\pm2\sqrt{14} }{4}\\\\\frac{-12\pm2\sqrt{14} }{4}\\\\\boxed{\frac{-6\pm\sqrt{14} }{2}}$

Hope this helps you.

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