braphi5609
26.11.2019 •
Mathematics
What are the solutions to the equation 2x^2 - 2x - 12 = 0?
a. x = -4, x = 3
b. x = -3, x = 4
c. x = -2, x = 3
d. x = -6, x = 2
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Ответ:
2(x)^2 - 2(x) - 12
(x)^2 - 6 - x
Multiply ↪1 (-6) = -6
1 + -6 = -5 , right?
-3 + 2 = -1, right?
After we have pulled out the like terms we have to add/subtract! x(x) - 3
Search for the common denominator
2(x) - 3
You can add up 4 for your terms
x + 2 (x - 3)
Make sure you solve this↪ 2 = 0
x + 2 = ?
x + 2 = 0
We have found the first; x = -2
Since, this one has a single variable, I'll make the step easier and quicker
Solve this part ↪ x-3 = 0
If we had the number 3 to your sides we would have found the outcome of the next x
So, the second x is 3
So, therefore your answer would have to be x =-2 ; x = 3 (most likely option C.)
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<Jayla>