What are the solutions to the quadratic equation below

Ответ:

BigCra

10.03.2022

First you must have the quadratic equal to zero. In order to do this you must subtract 7 to both sides

x^2 + 20x + (100 - 7) = 7 - 7

x^2 + 20x + 93 = 0

Now you must find two numbers who's sum equals 20 and their multiplication equal 93

Are there any? NO!

This means that you have to use the formula:

$\frac{-b±\sqrt{b^{2} - 4ac} }{2a}$

In this case:

a = 1

b = 20

c = 93

$\frac{-(20) plus/minus\sqrt{20^{2} - 4(1)(93)} }{2*1}$

$\frac{-20 plus/minus\sqrt{400 - 372} }{2}$

$\frac{-20 plus/minus\sqrt{28} }{2}$

^^^We must simplify √28

√28 = 2√7

so...

$\frac{-20 plus/minus 2\sqrt{7} }{2}$

simplify further:

$-10 plus/minus\sqrt{7$

-10 + √7

-10 - √7

***plus/minus = ±

Hope this helped!

~Just a girl in love with Shawn Mendes

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