What are the zeros of 3x^2+13x+14=2x^2-x-10

The correct answer is the second one: ±√15/3

 Explan ation:

 You have the quadratic equation 3x^2−10=−5. Then you must clear the variable "x" as below:

 3x^2−10=−5 
 3x^2=−5+10
 3x^2=5
 x^2=5/3
 x=±√(5/3)

 When you multipy the numerator and the denominator by 3 for simplify the result, you obtain:

 x=±√(5x3/3x3)
 x=±√(15/3²)

 When you simplify, you have:

 x=±√15/3