What are the zeros of the function? f(x)=2x3+6x2−8x

−4, 0, and 1

−1, 2, and 4

−4, 1, and 2

−1, 0, and 4

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Ответ:

lindsaymiklavic04

14.06.2020

Mathematics

Step-by-step explanation:

Hello, please consider the following.

$\text{We can notice that ****}\\\\\text{**** } x^2-4x+4=(x-2)^2\\\\\text{**** } y^2+8y+16=(y+4)^2\\\\x^2-4x+y^2+8y = (x-2)^2-4+(y+4)^2-16=-4\\\\(x-2)^2+(y+4)^2=-4+20=16=4^2$

The centre is (2,-4) and the radius is 4.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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What are the zeros of the function? f(x)=2x3+6x2−8x −4, 0, and 1 −1, 2, and 4 −4, 1, and 2 −1, 0, and 4