What is 2x + 4=10 what is the answer?

Ответ:

zitterkoph

10.09.2020

The answer would be x = 3.

First you would first subtract 4 from both sides.

This would make the equation 2x = 6

Then divide each side by 3 making the answer x = 3

2x + 4 = 10 - 4 -4

2. 2x = 6

÷2 ÷2

3. x = 3

0,0(0 оценок)

Val03

08.01.2021

we are given polynomial 2x^2 +4x +7.

we need to determine the number of roots of the given polynomial using the fundamental theorem of algebra.

a) for the given polynomial 2x^2+4x+7, we have degree =2.

therefore, according to the fundamental theorem of algebra, the polynomial can have at most 2 roots.

b) let us find the roots of the given polynomial.

2x^2+4x+7= 0

$\mathrm{for\: a\: quadratic\: equation\: of\: the\: form\: }ax^2+bx+c=0\mathrm{\: the\: solutions\: are\: }$

$\quad x_{1,\: 2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{for\: }\quad a=2,\: b=4,\: c=7: \quad x_{1,\: 2}=\frac{-4\pm \sqrt{4^2-4\cdot \: 2\cdot \: 7}}{2\cdot \: 2}$

$x=\frac{-4+\sqrt{4^2-4\cdot \: 2\cdot \: 7}}{2\cdot \: 2}=\quad -1+i\frac{\sqrt{10}}{2}$

$x=\frac{-4-\sqrt{4^2-4\cdot \: 2\cdot \: 7}}{2\cdot \: 2}=\quad -1-i\frac{\sqrt{10}}{2}$

therefore, roots are $x=-1+i\frac{\sqrt{10}}{2}, \: x=-1-i\frac{\sqrt{10}}{2}$ .

0,0(0 оценок)