Mathematics: What is jk rounded to the nearest hundredth show your work

What is jk rounded to the nearest hundredth show

isaiahhuettnerowgg8d

02.03.2023

$x^{\frac{3}{7}}$

Step-by-step explanation:

I'd assume your question is to simplify the expression $\sqrt[7]{x}*\sqrt[7]{x}*\sqrt[7]{x}$

There are 2 rules of exponents we are going to use to simplify this expression:

$\sqrt[n]{a} = a^{\frac{1}{n}}$ , and $a^{m}*a^{n}=a^{m+n}$

Using RULE 1, we can write the radicals [expression with roots] into exponential form [with a fractional exponent] like this:

$x^{\frac{1}{7}}*x^{\frac{1}{7}}*x^{\frac{1}{7}}$

Now, the bases are same, , and we have 3 powers. Using RULE 2, we can add the powers like this:

$x^{\frac{1}{7}+\frac{1}{7}+\frac{1}{7}}\\=x^{\frac{3}{7}}$

This is the simplified form.

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