What is m∠a ?

enter your answer in the box.

First of all let's consider triangle CDE
∠C + ∠D + ∠CED = 180° [Angle sum property]
43 + 35 + ∠CED = 180°
78 + ∠CED = 180°
∠CED =180- 78 = 102°
∠CED = ∠BEA [Vertically opposite angels are equal]

In Triangle ABR
∠A + ∠B + ∠BEA = 180° [Angle sum property]
∠A + 18 + 102 = 180°
∠A + 120 = 180°
∠A = 180 - 120
∠A = 60°

Therefore, m∠A = 60°

3x-3xy-2xy-5x+6. ( multiply the number that were outside the bracket)

By BODMAS rule...

= 3x-5x-3xy-2xy+6

= -2x-5xy+6

hope you understood...