miyah5316
11.07.2019 •
Mathematics
What is the answer if the sum of three numbers is 95 and the second number is three less than twice the first number and the third number is is ten less than three times the second?
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Ответ:
n + (2n - 3) + [3(2n - 3) - 10] = 95
n + (2n - 3) + [6n - 9 - 10] = 95
n + (2n - 3) + (6n - 19) = 95
n + 2n - 3 + 6n - 19 = 95
9n - 22 = 95
9n - 22 + 22 = 95 + 22
9n = 95 + 22
9n = 117
9n/9 = 117/9
n = 13
Ответ:
B
Step-by-step explanation:
i just did that!!! :)